17x^2+92x-150=0

Solution for 17x^2+92x-150=0 equation:

17x^2+92x-150=0

a = 17; b = 92; c = -150;
Δ = b2-4ac
Δ = 922-4·17·(-150)
Δ = 18664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18664}=\sqrt{4*4666}=\sqrt{4}*\sqrt{4666}=2\sqrt{4666}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(92)-2\sqrt{4666}}{2*17}=\frac{-92-2\sqrt{4666}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(92)+2\sqrt{4666}}{2*17}=\frac{-92+2\sqrt{4666}}{34}
$